You will
construct an tank (aquarium), the more indicated is glass because you need very
straight wall with 90 grades in the walls and in the encounters, but if the
object is very big you will construct a swimming-pool, and you will put the
object in the empty tank and start to fill counting the volume that you put,
like this you will fill with a jar of one liter,(the swimming-pool could you
count with ‘vazão’(flow) after you at least cover the object don’t will change
the final result if you fill more or less have to at least cover the object,
now you will, make the calculation of the volume of the tank, you don’t count
the walls they could be thick and that will influence in the result making it
wrong, so you measure only the inside, so you multiply the base that is width and extension (that will never change for the tank that you construct, like this you
construct a 90 for 70cm in base tank the height is the enough to cover the
objects that you will measure) and you will measure the height of the water and
not the height of the tank and the result will be in cm3 or m3,
if you used cm to calculate you will have cm x cm x cm, so you will have cm3,
and you will subtract the multiplication of the volume that you put in the
tank, if necessary make conversion of quantities, the volumes had to be in the
same quantity to do the subtraction, so all had to be in liters or in cm3for
instance, and you will have the volume of the object. Rute Bezerra de Menezes
Gondim
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