So see the red part doesn't existed for the 2nd equation, but even that I could assever tha the imaginary number would be in the red part, that up is the module of the number, even this way the imaginary number could be in another part of the sheet, phans asked me why I call those equations, see they are equations the problem of the equations is that when we have 2 incognitos and two equations we gonna find theorically the numbers, but with one equation, but see if is a equation! with one equation and two ingognitos we gonna find a range of numbers.

Rute Bezerra de Menezes Gondim