Alloys A and B are made up of two basic elements. In alloy A, the ratio of the elements is 7 : 5 and in alloy B it is 3 : 4. A new alloy is formed by mixing alloys A and B in a ratio of 5 : 4. What is the ratio of the basic elements in the new alloy?
A) 389 : 367
B) 390 : 368
C) 391 : 369
D) 392 : 370
E) 393 : 371
On these question how we gonna use the proportionalitites to sum, see that just sum 7 with 3 and multiply by 5, because the 7 parts of the metal is for a total of the first alloy and not for the second, so we gonna covert all the alloys to the same quantity, type if I was making alloy my mother explained to me is that way we had 10 cadinhos, and and never gonna got out of that is of the time og Jesus, so I can have 3 parts, but always 3 parts of 10, so I would never need convert is sacramentada, but in here the cadinhos are of diferernt numbers, I had a aunt that had a mine in Juazeiro, is the gold 8 quilates, is the gold mix with silver, she also sales gol from Portugal that was red with cooper in place of silver, so let's convert:
so is 7/12: 5/12 because we have 12 cadinhos for proportion of 7 to 5, so go got more one cadinho or kick if you have more than 7+5
The second is 3/7: 4/7 because I gonna have to have 3 cadinhos for a and more 4 cadinhos for b.
I fail here I mutliplpy the all the a for the same and is to mulyiply all the A for the same proportion, once my fahter said the problem of genius they simplfy and got mistaken.
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