In the game of basketball, each basket can be worth 1, 2 or 3 points to the team that scored the basket. The team that scores the most points wins the game.
In a particular game, Jorge “Golden Hand” made 17 baskets and scored a total of 36 points. It is also known that the number of 2-point baskets Jorge scored was three times the number of 1-point baskets he scored.
If x is the number of 1-point baskets, y is the number of 2-point baskets and z is the number of 3-point baskets scored by Jorge, then the product xyz is equal to
A) 108.
B) 120.
C) 134.
D) 135.
E) 180.
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Resolving again years after
1st we have that but the meaning because is the critics mathematic:
we know the value of the baskets
K - 1
L - 2
M - 3
When we work with two diferent types of incognits we could use the low case x, y, z and k, l, m
And also we can use one type in low case and the other in uppercase, when I soved I use uppercase and lower case and the normals, see K, L, M is used in the beggining because I notice that I gonna have to disappear with them to swap to x, y, z nothing about the question named like that is that I always use x, y and z, and K,L,M are temporary incognitos.
K - 1 - x
L - 2 - y
M - 3 - z
What is K, L, M the value of the baskets and x, y, z is the quantities of the basquets
So K + L + M = 17
xK + yL + zM = 36; here K=1, L=2,M=3 -> x + 2y + 3z = 36 (1eq)
y = 3x (2eq); x + 3x + z = 17 -> 4x + z = 17 -> z = 17 - 4x (3eq)
Replacing the the 2nd and 3rd equation in the 1st equation:
x + 2*3x + 3(17 - 4x) = 36; resolving: x = 3;
Replacing the x in the 2nd and 3rd equation : y = 3*3 = 9; z = 17 - 4*3 = 5.
x*y*z = 135.
But I justify for the professor that I would replace the 3 1st incognitos for new ones.
Rute Bezerra de Menezes Gondim
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